miércoles, 9 de mayo de 2012

Examen

Desarrollo
Pregunta 1
  Max =100*x1+120*x2;
  8*(2*x1+4*x2)<=48;
   4 *(4*x1+2*x2)<=63 ;
  2*(4*x1+4*x2)<=32;
Rows=      4 Vars=      2 No. integer vars=      0  ( all are linear)
 Nonzeros=     11 Constraint nonz=     6(     0 are +- 1) Density=0.917
 Smallest and largest elements in absolute value=    8.00000        120.000
 No. < :   3 No. =:   0 No. > :   0, Obj=MAX, GUBs <=   1
 Single cols=    0

 Optimal solution found at step:         1
 Objective value:                 300.0000

                       Variable           Value        Reduced Cost
                             X1        3.000000           0.0000000E+00
                             X2       0.0000000E+00        80.00000

                            Row    Slack or Surplus      Dual Price
                              1        300.0000            1.000000
                              2       0.0000000E+00        6.250000
                              3        15.00000           0.0000000E+00
                              4        8.000000           0.0000000E+00


 Ranges in which the basis is unchanged:

                                      Objective Coefficient Ranges
                                  Current        Allowable        Allowable
                Variable      Coefficient         Increase         Decrease
                      X1         100.0000         INFINITY         40.00000
                      X2         120.0000         80.00000         INFINITY

                                           Righthand Side Ranges
                     Row          Current        Allowable        Allowable
                                      RHS         Increase         Decrease
                       2         48.00000         15.00000         48.00000
                       3         63.00000         INFINITY         15.00000
                       4         32.00000         INFINITY         8.000000

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